Display results in form fields?

I'm relatively new to PHP programming and I am trying to create a web application using your form generator and validation class. I have many individual forms that are used to maintain multiple MySQL database tables.

All my forms are self-submitting and work just fine without your class. However, I would like very much to change them to use your class, mostly because of the excellent built-in validation methods.

Each of my form pages handles the entire C-R-U-D procedure, using a switch statement to decide which procedure to implement.

When I READ in a table row, I need the values to display in the form so that they can be edited if necessary. However, I can not figure out how to do that with your class. I've tried adding "VALUE"=>"$someVariable" to the AddInput arrays, but that doesn't seem to work. It was the only thing I could think to do.

I would appreciate some help or advise.

Also, are there any working example scripts other than the test_form.php that you enclose with the class? I would like to see one that interfaces with a database so that I can see exactly where to place my form handler code.

Thanks in advance.

Best,

Jim

You can use the scaffolding plug-in to generate forms integrated with CRUD operations. That plug-in was developed precisely for that purpose. It even provides some AJAX form submission support.

Take a look at the test_scaffolding_input.php example script. You can view it here in action:

meta-language.net/forms-examples.ht ...

There is also a blog article about this plug-in here:

phpclasses.org/blog/package/1/post/ ...

Thank you, Manuel. I'll take a look at those and get back if I have other questions.

Much appreciated.

Jim